Chemistry, asked by luchfaucher, 11 months ago

Calculate the pOH of 0.075mol/L Ca(OH)2(aq).

Answers

Answered by Raasheedhaa

0

Answer:

POH=0.8 is the correct answer

Answered by merlinelizabethsunny

0

Answer:

Explanation:

pOH= -Log[OH ions]

[oh ions]=75×10^-3×2 Ca(OH)₂⇒ ca₊ + 2 OH

pOH=-log( 15×10^--2)=2-log15=2-1.17=0.83

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