Question

Calculate the pOH of a solution at 25∘C that contains 1×10−10M of hydronium ions, i.e. H3O+;

Answer 1

pOH=−log10[−OH]=5.60

Explanation:

We know or should know that under standard conditions (the which operate here): pH+pOH=14.

pH=−log10[H3O+] = −log10[3.98×10−9]=8.40.

And thus pOH=14−8.60=5.60

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