Question

calculate the poh of a solution whose hydrogen ion concentration is 0.1 M. what is the nature of the solution​

Answer 1

Given :

$\sf [H^+] \:=\: 0.1\:M$

To find :

1. pOH
2. Nature of solution

Solution:

We know that ,

➝ pH + pOH = 14

➩ pOH = 14 - pH

Also,

$\sf \: pH \:=\:(-) \: \log( \: [H^+] \: )$

$\sf \implies \: pOH\:=\: 14 - \bigg[ \:(-) \: \log( \: [H^+] \: )\:\bigg]$

$\sf \implies \: pOH\:=\: 14 \: + \: \log( \: 0.1\: )\:$

$\sf \implies \: pOH\:=\: 14 \: + \: log( \frac{1}{10} )$

$\sf \implies \: pOH\:=\: 14 \: + \: log( {10}^{ - 1} )$

$\sf \implies \: pOH\:=\: 14 \: + \: ( - 1)log( 10 )$

$\sf \implies \: pOH\:=\: 14 \: + \: ( - 1)(1)$

$\sf \implies \: pOH\:=\:14 - 1$

$\sf \implies \: pOH\:=\: 13$

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As pOH of solution is 13 , in other terms pH. of solution is 1 , therefore the given solution is acidic.

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