Question

calculate the point along the line joining the centres of earth and moon where there is no gravitational force ( Me=6*10^24kg, Mm=7.4*10^22kg ,d=3.8*10^8)​

Answer 1

a)

F

=

G

(

m

1

)

(

m

2

)

r

2

F

=

(

6.67300

×

10

−

11

)

(

7.34

⋅

10

22

k

g

)

5.97

⋅

10

24

k

g

(

3.8

⋅

10

8

m

)

2

=

2.025

⋅

10

20

b) The field is just G(m)/r^2

(

6.67300

⋅

10

−

11

)

5.97

⋅

10

24

k

g

(

3.8

⋅

10/8m)2=0.002759

HOPE IT HELPS.

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Answer 2

Explanation:

as per newton's law

F = GMm/R²

a = F/m = GM/R²

we find that point where force from earth and moon are equal

so that

a = earth acceleration - moon acceleration = 0

earth = moon

=> GMe/R² = GMm/R'²

=> distance is same so that R = R

and distance from moon R' = 3.8*10^8 - R

=> Me/Mm = R²/(3.8*10^8 - R)²

=> (6*10^24)/7.4*10²² = R²/ ( 3.8*10^8 - R) ²

=> 81.3 = R²/( 3.8*10^8 - R) ²

=> R = (3.8*10^ - R)*9.0166

R = 346,024km