Question

Calculate the position of an object placed 30 cm away from a concave lens focal length 15. Also calculate the magnifying power of the lens​

Answer 1

Answer:

see up in photo full explanation with steps

Answer 2

Answer: given : i) distance of object(u) = 30cm

ii) focal length of lense= 15

to find position of image (v) = ?

soln: - 1/f = 1/v - 1/u

1/15 = 1/v - 1/30

1/v = 1/30 - 1/15

1/v = 15 - 30/450

1/v = -15/450

v = 450/-15

V = -30

Therefore postion of imapge is -30cm

Explanation: