Question

calculate the possible values of x,if the standard deviation of numbers 2,3,2x,11 is 3.5.​

Answer 1

Answer:

Standard Deviation (σ) = 3.5.

Standard Deviation (σ) = 3.5.Sum of observations: 2 + 3 + 2x + 11 = 16 + 2x.

Standard Deviation (σ) = 3.5.Sum of observations: 2 + 3 + 2x + 11 = 16 + 2x.Total number of observations = 4.

Standard Deviation (σ) = 3.5.Sum of observations: 2 + 3 + 2x + 11 = 16 + 2x.Total number of observations = 4.Mean = (16 + 2x)/4 = (8 + x)/2.

Standard Deviation (σ) = 3.5.Sum of observations: 2 + 3 + 2x + 11 = 16 + 2x.Total number of observations = 4.Mean = (16 + 2x)/4 = (8 + x)/2.12.25 × 16 = 280 – 64x + 12x2

Standard Deviation (σ) = 3.5.Sum of observations: 2 + 3 + 2x + 11 = 16 + 2x.Total number of observations = 4.Mean = (16 + 2x)/4 = (8 + x)/2.12.25 × 16 = 280 – 64x + 12x2196 = 280 – 64x + 12x2

Standard Deviation (σ) = 3.5.Sum of observations: 2 + 3 + 2x + 11 = 16 + 2x.Total number of observations = 4.Mean = (16 + 2x)/4 = (8 + x)/2.12.25 × 16 = 280 – 64x + 12x2196 = 280 – 64x + 12x212x2 – 64x + 84 = 0.

Standard Deviation (σ) = 3.5.Sum of observations: 2 + 3 + 2x + 11 = 16 + 2x.Total number of observations = 4.Mean = (16 + 2x)/4 = (8 + x)/2.12.25 × 16 = 280 – 64x + 12x2196 = 280 – 64x + 12x212x2 – 64x + 84 = 0.or 3x2 – 16x + 21 = 0.

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