Question

Calculate the potential at a point P at a distance of 30cm from a point charge q=20 u C

Answer 1

Hello!

• R = $\bf{0.3\: m}$
• q = 20um = $\bf{2 \:x\:10^{-5}}$

$\underline{\sf Then}$,

v = $\dfrac{\sf 1}{\sf 4}$π ∈ $\dfrac{\sf q}{\sf r}$

⇒ v = $\dfrac{\sf 9\:x\:10^{9} \:x\:2 \:x\: 10^{-5}}{\sf 0.3}$

⇒ $\bf{v}$ = $\boxed{\sf 6 \:x\: 10^{5} \:Volt}$

Cheers!

Answer 2

Answer:

v= 6*10⁵ volt

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