Physics, asked by attatul6092, 1 year ago

calculate the potential at a point p due to a charge of 4×10^-7 located 9 cm away

Answers

Answered by Bhavy06
4
potential= kq/r

so v= 9×10^9 * 4×10^-7/9cm into m

36×10^2/9×10^-2
4+×10^4 is yr answrr
Answered by Anonymous
1

Potential difference at a point  

It is defined as the work to move or bring a charge from one. Point to another point  

 Now coming to the question  

We need to calculate <b> potential difference at a point p  

 ((A)) v = 1/4π£₀ Q/r  

We know That 1/4π£₀ = 9 x 10^9  R = 9cm  

= 0.09 m  

Q= 4 x10^-7C  

By applying these values to the formula  

9 x 10^9 x 4x10^-7 /0.09

 4 x 10^4V\\ //  

Now we need to calculate

 To obtain the work done  

((B)) W = qV    

q = 2 x 10^-8 C

V = 4 x 10^4

= w =?

W = qV

= 2 x 10^-8 X 4x10^4

= 8X10^6 J //

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