Question

Calculate the potential at P due to a charge 6 * 10^-7 C at a distance of 10 m. Also find the work
required in bringing a charge of 3 * 10^-9 C from infinity to P.​

Answer 1

Answer:

• v
• $v = kq \div r$
• esse work nikalo
• $v = w \div q$

Answer 2

Answer:

The potential at a point P is due to a charge of 6 * 10^-7 C which is at a distance of 10m from the charge is 540J/C, the work  required in bringing a charge of 3 * 10^-9 C from infinity to P is $1.6*10^{-6}J$

Explanation:

• The potential due to a charge (q) at a distance (r) from it is given by the formula   $V=Kq/r$

From the question, we have

the charge $q=6*10^{-7}C$

distance to the point P $r=10m$

⇒ the potential at that point $V=\frac{9*10^{9}*6*10^{-7} }{10} =540J/C$

• The work done to  bring a charge from infinity is nothing but the product of potential at that point and charge $W=Vq$

we have given that

the charge is $q=3*10^{-9}C$

potential at that point is calculated as $V=540J/C$

⇒ work done $W=540*3*10^{-9} =1.6*10^{-6}J$