Calculate the potential difference across the ends of a wire of resistance 6 ohms when a (3)
current of 1.5 A passes through it.
Answers
Answered by
2
Answer:
As we know that
V=IR
V=6x1.5
v=9V
Answered by
2
Explanation:
so aur formula id V=IR
resistance is 6 ohms
current is 1.5 ampers
V =I ×R
V=6×1.5
V=9.0
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