Question

Calculate the potential difference between the two terminals of a battery, if 150 joules

of work is required to transfer 20 coulombs of charge from one terminal of the battery

to the other.​

Answer 1

Explanation:

V=W/Q or Volt=Joule/Coulomb

v=150Joule/20coulomb

voltage=15/2

=7.5Volt

P.d. or Voltage of battery is 7.5 Volt

thanks

Answer 2

$\mathtt{\huge{ \fbox{</strong><strong>Solution</strong><strong> :)}}}$

Given ,

• Work done (w) = 150 joule
• Charge (q) = 20 coulomb

We know that ,

Work done to move a unit charge from one point to another point is called potential difference

$\mathtt{ \fbox{Potential \: difference \: (v) = \frac{w}{q} }}$

Thus ,

v = 150/20

v = 7.5 volt

Hence , the potential difference is 7.5 volt

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