Calculate the potential difference between two plates when they are separated by a distance of a 0.005m and are able to hold an electron motionless between them. (Mass of electron = 9.1x10–31 Kg)
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Answer:
COULOMB’S LAW
F=k∣q1q2∣r2F=k∣q1q2∣r2
Coulomb’s law calculates the magnitude of the force F between two point charges, q1 and q2, separated by a distance r. In SI units, the constant k is equal to
k=8.988×109N⋅m2C2≈8.99×109N⋅m2C2k=8.988×109N⋅m2C2≈8.99×109N⋅m2C2
The electrostatic force is a vector quantity and is expressed in units of newtons. The force is understood to be along the line joining the two charges.
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