Calculate the potential difference , if there are 5000 charge carrier are flowing for 10 min through a resistance of 100 ohm
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Answered by
20
Given ⇒
Charge (Q) = 5000 C.
Time = 10 min.
= 10 × 60 = 600 seconds.
∴ I = Q/t
= 5000/600
= 50/6
= 25/3 A.
R = 100 Ω
Using Ohm's law,
V = I × R
⇒ V = 25/3 × 100
⇒ V = 2500/3
∴ V = 833.33 V.
Hence, the Potential difference is 833.33 V.
Hope it helps.
Charge (Q) = 5000 C.
Time = 10 min.
= 10 × 60 = 600 seconds.
∴ I = Q/t
= 5000/600
= 50/6
= 25/3 A.
R = 100 Ω
Using Ohm's law,
V = I × R
⇒ V = 25/3 × 100
⇒ V = 2500/3
∴ V = 833.33 V.
Hence, the Potential difference is 833.33 V.
Hope it helps.
Answered by
0
Answer:
Explanation:
833.33
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