Question

Calculate the potential energy possessed by a mango of mass 1.2kg hanging on a tree of height of 10m (Take g = 10ms-2)

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Potential\:energy=120\:J}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Mass (m) = 1.2 \: kg \\ \\ \tt: \implies Height (h) = 10 \: m \\ \\ \tt: \implies Acceleration(a) = 10 { \: ms}^{2} \\ \\ \red{\underline \bold{To \: Find : }} \\ \tt: \implies Potential \: Energy(P.E) = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Potential \: Energy = mgh \\ \\ \tt: \implies Potential \: Energy =1.2 \times 10 \times 10 \\ \\ \green{\tt: \implies Potential \: Energy = 120 \: J} \\ \\ \green{\tt \therefore Potential \: Energy \: possed \: by \: mango \: tree \: is \: 120 \: J} \\ \\ \blue{ \bold{Some \: related \: formula : }} \\ \orange{\tt \circ \: Kinetic \: Energy = \frac{1}{2}m {v}^{2} } \\ \\ \orange{\tt \circ \:Work \: Done =Force \times Displacement}$

Answer 2

$\huge\sf{Answer:}$

☆ Given:

⇏ A mango of mass 1.2 kg hanging on a tree of height of 10 m.

☆ Find:

⇏ Calculate the potential energy.

☆ Given value:

⇏ [g = 10ms -2]

☆ Know terms:

⇏ Mass = (M)

⇏ Height = (h)

⇏ Acceleration = (a)

⇏ Gram = (g)

⇏ Potential energy = (PE)

⇏ Joule = (J)

☆ Using formula:

⇏ $\sf PE = M \times g \times h$

☆ Calculations:

⇏ $\sf PE = 1.2 \times 10 \times 10$

⇏ ${\sf{\underline{\boxed{\sf{PE = 120 \:J}}}}}$

Therefore, 120 joule is the potential energy.