calculate the potential of hydrogen electride placed in a solution of ph 10
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Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10. 2Fe²+ (aq) + I2(s) has E0cell = 0.236 V at 298 K.
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For hydrogen electrode, , it is given that pH = 10
∴[H+] = 10 - 10M
Now, using Nernst equation:
= - 0.0591 log 1010
= - 0.591 V
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