Question

Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.

Answer 1

p H = 10
Using formula [H+] = 10-pH
So [H+] = 10-10 M
Electrode reaction will be
H+ + e- → ½ H2
Use the formula
Value of E0 = 0
Ecell = E0 - 0.0591 log[H2]
1 [H+]
Ecell = - 0.0591 log( 1/10-10)
1
Ecell = - 0.0591 ( 10) = -0.591 V
1

Answer 2

Answer:

Explanation:

We know Ecell=Eo cell-0.059/1 log([H2]/[H^+])

For hydogen Eo cell=0

Ecell=-0.059/1 log{1/10^-10}

Ecell=-0.059*10

Ecell= -0.591 volts

Please mark as brainliest and thank if it helps...