Question

Calculate the potential of the following cell at 25° Sn(s)| Sn² (0.025M)||Ag (0.015M)Ag(s)

Answer 1

Answer:

Explanation:

E= 0.0592/2 ( log k)

Sn(s) + 2Ag(s)+1 ⇒Sn² +2 Ag

log k = 0.025/(0.015M)^2

= 0.11

E= 0.0296 log 0.11

= 0.0296*(-0.96)

= -0.0284 V