Calculate the potential of the following cell at 25°C
Zn | Zn²⁺ (0.6M) || H⁺ (1.2M) | H₂(g, 1atm) | Pt
E⁰Zn = -0.763V.
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Answer:
+0.763V
Explanation:
Reduction potential of H is 0 and zinc is -0.763V , it means reduction potential of hydrogen is more than zinc. Zinc has greater capability to get oxidized.
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