Calculate the potential of the following electrochemical cell at 25oC.
Cu(s) / Cu+2 (0.5M) // H+
(0.01) / H2 (0.95 atm) /Pt. Given Ca
thode =0.00V; Eo
anode =0.34V.
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Explanation:
Calculate the potential of the following electrochemical cell at 25oC.
Cu(s) / Cu+2 (0.5M) // H+
(0.01) / H2 (0.95 atm) /Pt. Given Ca
thode =0.00V; Eo
anode =0.34V.
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