Question

calculate the power developed by a 110 Kg man climbing up a vertical stairway at the rate of 2.0m/s . take g = 9.8 m/s^2

Answer 1

mass = 110 kg
velocity (v) = 2 m/s
let, initial velocity = 0 m/s
therefor K.E = 1/2mv² = 1/2*110*4 = 220 J
now,
power = energy / time = 220/t  
time = ?
now
v = u + at
2 = 0 + 9.8t
2 = 9.8t
20/9.8 = t
2.04 sec = t
now power = 220/2.04 = 22000 / 204= 107.84 W

i hope it helps...........

Answer 2

Answer:

Explanation:

Solution :-

Given :-

Mass, m = 110 kg

Acceleration due to gravity, g = 9.8 m/s²

Distance covered in 1 seconds, d = 2.0 m

To Calculate :-

Power, P = ??

Formula to be used :-

P = W/t

But W = mgd

P = mgd/t

Substituting the given values, we get

P = 110 × 9.8 × 2/1

P = 2.56 W

Hence, the power developed by a 110 Kg is 2.56 W.