Question

Calculate the power dissipated when a current of
4mA flows through
ours through a resistance of 5Kohm​

Answer 1

According to Ohm's power equations, P=(I^2)R.

So, I=4 mA, or 0.004A, and R=5 Kohm, or 5000 ohms.

Plugging in the values, P=(. 004^2)5000, or P=0.000016x5000, thus P=0.08W or 80 mW.

HOPE THIS HELPS YOU!!!

Answer 2

Answer in picture | Use Ohm's Law formula is P = Isq R