calculate the power of a converging lens that forms the image at 50 cm of an object kept at hundred cm from the lens
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Given –
- Converging lens (Convex lens)
- Image distance = 50 cm
- Object Distance = -100 cm
To Find –
- Power of the lens
Solution –
Lens Formula : 1/v - 1/u = 1/f.
Substituting the values,
➸ 1/-100 - 1/50 = 1/f
➸ -1/100 - 1/50 = 1/f
➸ (-50 - 100)/5000 = 1/f
➸ -150/5000 = 1/f
➸ 1/f = -15/500
➸ 1/f = -3/100
➸ 1/f = -0.03
➸ f = 1/-0.03
➸ f = -33.33 cm
Power of the lens = P = 1/f.
➸ P = 1/-33.33
➸ P = -0.03 D
Focal length of the lens is -33.33 cm and Power of the lens is 0.03 D.
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