Question

calculate the power of a motor which is capable of raising of water in 5 min from a well 120 m deep

Answer 1

Hi 

Here is your answer,

Here, the volume of water raised V = 2000 L 

                  Density of water ρ = 1 kg/L

∴∴ Mass of water raised, m = Vρ = 2000 × 1 = 2000 Kg 


Power, P = W/t = mgh/t = 2000 × 9.8 × 120/ 5 × 60 

                                        = 780 W

               = 7.840 kW                                     [ 1Kw = 1000 W]




Hope it helps you !