calculate the power of an appliance of resistance 529 ohm that works in 230v) *
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We have,
P=15W,voltage v=250v
So,
(i) Electric current drawn,
1=
v
p
=
250
1500
=6A
(ii) Energy consumed, E=power×time
=1500×60
=9000
(iii) Cost of energy consumed
=90×2.50
=Rs225
P=15W,voltage v=250v
So,
(i) Electric current drawn,
1=
v
p
=
250
1500
=6A
(ii) Energy consumed, E=power×time
=1500×60
=9000
(iii) Cost of energy consumed
=90×2.50
=Rs225
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