Question

Calculate the power of an electic motor that can lift 800kg of water in a tank at a height of 1500cm in 20s. (g=10m/s^2

Answer 1

Answer:

Power of an electric motor is 6000 watt.

Explanation:

Given,

m = 800 kg

h = 1500 cm

100 cm = 1m

h = 1500/100 m

h = 15 m

g = 10 m/s^2

t = 20 seconds

P = W/t

P = mgh/t

P = (800 × 10 × 15)/20 watt

P = 120000 / 20 watt

P = 6000 watt

Here,

m is the mass of water.

h is the height of water in the tank.

g is the acceleration due to gravity.

t is the time taken.

P is the power of an electric motor.

W is the work done.

Hence,

Power of an electric motor is 6000 watt.