Question

Calculate the power of an electric motor that can lift 400 kilogram of water to store in a tank at a height of 1500 CM in 20s

Answer 1

M=400kg

g=9.8m/s

h=1.5m

First we will find work done

W=m*g*h

=400*1.5*9.8

=5880joules

Because power =

work done /timetaken

=5880/20

=294watts