Question

Calculate the power of an electric motor that can lift 800 kg of water to store in a tank at a height of 1500cm in 20s. (g=10m/s2)

Answer 1

we have,
m=800kg
h=1500cm
=15m
g=10m/s2
Now,P.E.=mgh
=800×10×15
=120000J
now,t=20s
now,P=E/t
=120000/20
=6000W