Question

calculate the power of an electric motor that can lift 800kg water to store in a tank at a height of 1500cm in 20sec?take g-20ms2

Answer 1

Mass, m = 800 kg
Height, s = 1500 cm = 1.5 m
Time, t= 20 s
Gravity = 10m/s²

(You have given 20 m/s² ; but its normally taken 10 m/s² ; I think u have done typing mistake )

Power = Work/Time


Work = Fs
= 800×10×1.5
= 12,000 J

Power = 12000/20 = 600 W


Or if g = 20 m/s²
Then,
Mass, m = 800 kg
Height, s = 1500 cm = 1.5 m
Time, t= 20 s
Gravity = 20m/s²
Power = Work/Time


Work = Fs
= 800×20×1.5
= 24,000 J

Power = 24000/20 = 1200 W