Question

Calculate the power of an engine required to lift 10 kg of coal per hour from a mine

(Take g= 10 ms?)​

Answer 1

Answer:

m=10

5

kg,g=10ms

−2

,h=360m,t=1h=3600s

The work needed in lifting a mass m to a height h against the force due to gravity is W=mg×h

And, power, P=

t

W

=

t

mgh

p∴P=

3600

10

5

×10×360

W=10

5

W=100kW