Question

calculate the power of an engine required to lift 10 power 5 kg of coal per hour from a mine 360 metre Deep. Take g=10m/sec^2​

Answer 1

Explanation:

The answer of question in figure .

Thank you

Answer 2

Answer:

Explanation:

Power=mgh/t

=10^5×5×360/3600

=100W

Hope thse helps u to understand my ans