Math, asked by mahanaatma, 1 year ago

calculate the power of an engine required to lift 100000 kg of coal from mine 360m deep.take g=10m/s

Answers

Answered by divyanshgupta351

0

mgh/t = 100000×10×360=360000000watt

Answered by Eshita111

2

mgh/t
100000*10*360/1
calculate the answer
pls mark my answer as brainliest!!!!

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