Physics, asked by kushaalsachdeva, 1 year ago

Calculate the power of an engine required to lift 105 kg of coal per hour from a mine 360 m deep.

[Take g = 10 ms-2]

Answers

Answered by Anonymous

2

Answer:

the power of an engine required to lift 105 kg of coal per hour from a mine 360 m deep =100 kw

Answered by help7oo645o984

2

Answer:

P = mgh/t = 360 x10 x 105 J/3600s

=105watt

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