Physics, asked by mariamathews500, 20 days ago

Calculate the power of an engine required to lift 108 kg of coal per hour from a mine 360 m deep (Take g=10m/s2 ).

Answers

Answered by raibhumika760

Answer:

1080

Explanation:

solun

mass ( m )= 108kg Time ( T ) = one hour (360sec) , Height ( h)=360m, Now, Power(p) =w/t ( p) =m*g*h/t (p) = 108*10*360/360 Power(p) =1080 watt (ans)....

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