Question

calculate the power of an engine required to lift 900 kg of coal per hour from a mine whose depth is 300 g=10​

Answer 1

Explanation:

Hey there!

Mistakes in the question!

Question will be ---->

Calculate the power of an engine required to lift 900 kg of coal per hour from a mine 300m deep.

Answer----->

Mass(m) = 900 kg = 30² kg

Height (h) = 300m

Acceleration due to gravity = 10 m/s^2

Time(t) = 1 hour = 3600 s

Then,

P.E = mgh

      = 30² * 10 * 300 J

Work done = P.E = 30² * 10 * 300 J

We know,

Power = Work done / Time

            = 30² x 10 x 300/3000

            = 30² watt.

Hope this helps you

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