Question

Calculate the power of an engine to lift 10^4 kg of coal per hour from a 300m deep mine.(g = 10m/s^2)

Answer 1

M = 10^4 = 10000kg
g = 10
h = 300m
T = 1Hr

E = mgh

E = 10000 * 10 * 300

E = 3 * 10^7 J

Now to find power

P = E * T

P = 3*10^7 * 1

P = 3*10^7 joule.Hr


Thanks