Question

calculate the power of an engine which can just pull a train of mass 5 ×10^5 kg in an incline of 1 in 50 at the rate of 54 km/h. the resistance due to friction is 0.8 N/quinal.... (correct and satisfying answer will be marked as Brainlist)​

Answer 1

Answer

m = mass of the train = 25000 quintal = 25000 x 100 kg = 2.5 x 10⁶ kg

Sinθ = 1/100

F_{g}F

g

= parallel component of force of gravity acting on the train = mg Sinθ = (2.5 x 10⁶) (9.8) (1/100) = 245000 N

f' = frictional force acting per quintal of train = 2 N

f = total frictional force acting on the train = m f' = 25000 x 2 = 50000 N

F = force at which the train pulls

a = accelerattion of the train = 0 m/s

force equation for the motion of train is given as

F - F_{g}F

g

- f = ma

F - 245000 - 50000 = m (0)

F = 295000 N

v = speed of the train = 10.8 km/h = 10.8 (5/18) m/s = 3 m/s

Power of the engine is given as

P = F v

P = (295000) (3)

P = 8.85 x 10⁵ Watt

I hope the answer will help you.