Question

Calculate the power of the engine of a1500 kgcar, which can acceleratefrom 18 km/ph to 36 km/ph in 5 seconds.

Answer 1

Answer :-

Given parameters

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

[latex]u = \frac{18\times 1000}{60\times 60s}[/latex]

u = 5 m/s

Final velocity (v) =36km/hour

[latex]v = \frac{36\times 1000}{60\times 60s}[/latex]

v =10 m/s

We need to calculate acceleration and distance travelled

We know that

acceleration a = (v – u)/t

Substituting the given values in the above equation we get,

a = (10 – 5)/5

a =5/5

a = 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled S =37.5 m