Question

Calculate the power used in the 2 Ω resistor in each of the following circuits:; (i) a 6V battery in series with 1 Ω and 2 Ω resistors.; (ii) a 4 V battery in parallel with 12 Ω and 2Ω resistors.

Answer 1

Explanation:

(i) Req = 1+2=3ohm

P=v²/r

=6²/3

=36/3

=12 watt

(ii) 1/Req = 1/12+1/2

=1+6/12

= 7/12

Req=12/7

Power = 4²/12/7

= 16×7/12

=28/3 watt

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Answer 2

Answer:

Ans. (c) 20J

Explanation: Total resistance of combination = 2ohm+4ohm= 6ohm

Current through the circuit can be calculated as follows:

$i = \frac{v}{r}$

which is =6v/6ohm=1A

Heat dissipation by 4ohm can be calculated as follows:

H=I²Rt = (1.4)² x 4ohm x 5s = 20J

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