Question

Calculate the pressure applied by the brick when kept upright apply on ground. Force = 20N, Dimensions = 25cm, 10cm, 5cm​

Answer 1

Explanation:

Since pressure-Force/Area

when it is placed upright its length and breadth will be 10 & 5 respectively so area=10*5=50cm

2=0.005m2

Pressure=2.5N/0.005m2

=500N m-2 in case b it is placed on widest base i.e.25cm

so area =25*10=2500cm2

=0.25m2

Pressure=2.5/0.25=10N m-2

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Answer 2

Answer:

Let P1,P2 and P3 be the pressures exerted by the brick while resting on different faces.

The dimensions of the given brick are 20cm×10cm×5cm

Case (i) : When the block is resting on 20cm×10cmface.

Thrust acting= Weight of the brick

T=500gwt

Area of constant (A)=20cm×10cm

Pressure exerted (P1)

=AreaThrust=20×10500

∴P1=2.5gwtcm−2

Case (ii) : When the block is resting on 20cm×5cmface

Thrust= Weight of the brick

=500gwt

Area of constant (A)=20cm×5cm

Pressure exerted

(P2)=AreaThrust=20×5500

∴P2=5gwtcm−2

Case (iii) : When the block on 10cm×5cmface

Thrust= Weight of the brick =500g.wt.

Area of contact =10cm×5cm

Pressure=