Question

Calculate the pressure at a depth of 2m in a swimming pool filled with water

Answer 1

Question:-

Calculate the pressure at a depth of 2 m in a swimming pool filled with water.

Answer:-

$\Large\boxed{\quad\sf{1.2\times10^5\ Pa\quad}}$

Solution:-

The pressure difference between the pressure at the depth 2m below the surface and the pressure at the surface of water is,

$\longrightarrow\sf{P-P_0=\rho gh}$

where,

• $\sf{P=}$ pressure at the depth

• $\sf{P_0=}$ atmospheric pressure = $\sf{10^5\ Pa}$

• $\rho=$ density of water = $\sf{10^3\ kg\ m^{-3}}$

• $\sf{g=10\ m\ s^{-2}}$

• $\sf{h=2\ m}$

Thus,

$\longrightarrow\sf{P=P_0+\rho gh}$

$\longrightarrow\sf{P=10^5+10^3\times10\times2}$

$\longrightarrow\sf{P=10\times10^4+2\times10^4}$

$\longrightarrow\sf{\underline{\underline{P=1.2\times10^5\ Pa}}}$

Answer 2

Answer:

20000Pa

Explanation:

1. formular of p; density *gravity*height
2. p;1000kg/m/m*10 N * 2m
3. p;20000Pa