Question

Calculate the pressure at the bottom of an ocean at a depth of 1500 m. Take
the density of sea water 1.024 × 103 kg m–3, atmospheric pressure=1.01 × 105
Pa and g = 9.80 ms–2.

Answer 1

using concept,

P = P0 + ρgh

where, P is pressure at the bottom of the ocean, P0 is atmospheric pressure, ρ is density of sea water , g is acceleration due to gravity and h is depth .

here given,

P0 = 1.01 × 10^5 Pa

ρ = 1.024 × 10³ kg/m³

g = 9.8 m/s²

h = 1500 m

so, P = 1.01 × 10^5 + 1.024 × 10³ × 9.8 × 1500

= 1.01 × 10^5 + 15052.8 × 10³

= 1.01 × 10^5 + 1.5052 × 10^7

= 0.0101 × 10^7 + 1.5052 × 10^7

= 1.5153 × 10^7 Pa