Question

calculate the pressure due to a liquid column of height 50m and density 2*10³kg¯³. Take g=9.8ms¯²​

Answer 1

${\huge{\rm{\underline{\underline{Question:-}}}}}$

Q) Calculate the pressure due to a liquid column of height 50 m and density 2×10³ kg/m³ . Take g = 9.8 m/s² .

Answer :–

★ Given :-

• h = 50 m
• density = 2×10³ kg/m³
• g = 9.8 m/s² .

★ To Find :-

• Pressure

★ Solution :-

Pressure = Density × g × h

=> Pressure = 2×10³ × 9.8 × 50

=> Pressure = 100×10³×9.8

=> Pressure = 9.8 × 10⁴ pascals .

★ Know More :-

• Pressure : It is the perpendicular force per unit area .
• The units of pressure - N/m² ,kg/m•s² , Pascal
• Dimensional Formula = [ML-¹ T-²]
• p = F/a
• $\rho$ - density .
• density is mass of a unit volume of ant substance .
• d = M/V .

Answer 2

Given :-

Height = 50 m

Density = 2 × 10³ kg/m³

To Find :-

The pressure due to a liquid column.

Analysis :-

Here we are given with the height, density and the gravity.

In order to find the pressure substitute the given values from the question accordingly such that pressure is equal to density into gravity into height.

Solution :-

We know that,

• h = Height
• g = Gravity
• p = Pressure
• d = Density

Using the formula,

$\underline{\boxed{\sf Pressure=Density \times Gravity \times Height}}$

Given that,

Density (d) = 2 × 10³ kg/m³

Gravity (g) = 9.8 m/s¯²​

Height (h) = 50 m

Substituting their values,

⇒ p = (2 × 10³) × 9.8 × 50

⇒ p = 19600 × 50

⇒ p = 980000 Pa = 9.8 × 10⁵ Pa

Therefore, the pressure due to a liquid column is 9.8 × 10⁵ Pa.