calculate the pressure due to a water column of height 100 m ( g=10m/sec² and density of water 10³kg/m³)
Answers
Answered by
2
Explanation:
Pressure will remain same for both the liquids.
Hence, Pressure = ρ×g×h
ρ = density of the liquid
g = acceleration due to gravity
h = height of the column
⟹ρ
mercury
×g×h
mercury
=ρ
water
×g×h
water
⟹ρ
mercury
×h
mercury
=ρ
water
×h
water
Given, ρ
mercury
=13.6 h
mercury
=70
ρ
water
=1 h
water
=?
Hence,
h
water
=
1
13.6×70
h
water
=952cm
Answered by
1
Explanation:
And the final answer is 10^6 Nm^-2
Hope it helps....
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