Calculate the pressure due to a water column of height 100m.(take g =10 ms^2 qnd density of water =1000 kg m ^3)
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We have to find the pressure due to a water column of height 100 m.
Given :
- g = acceleration due to gravity = 10 m/s²
- ρ = density of water = 1000 kg/m³
- h = height of water column = 100 m
We know , the pressure due to a water column of height ‘h’ is given by, P = ρgh
= 1000 kg/m³ × 10 m/s² × 100 m
= 10⁶ N/m²
Therefore the pressure due to a water column of height 100 m is 10⁶ N/m².
[ note : Pressure is the force applied in a specific area. so, P = F/A ,
- let the mass of water = m
- and density of water is ρ ,
- if the base area of column is A and height of water is h then Volume of water , V = Ah
- and mass of water , m = ρAh
- force applied = weight of water = mg = ρAhg
- now pressure, P = (ρAhg)/A = ρgh
hence, P = ρgh ,
now you got the formula of pressure at a water column of height h, didn't you? ]
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