Calculate the pressure exerted by 0.12 m vertical length of alcohol of density 0.12 gcm-3 in SI units. (Take g =10 ms-2)
Answers
Answered by
0
Explanation:
pressure = density × acceleration due to gravity × height
= 0.12×10 ×0.12= 0.144
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Answered by
0
Explanation:
Density of alcohol (d)=0.8gcm
−3
=0.8×1000=800kgm
−3
[∴1gcm
−3
=1000kgm
−3
]
Pressure=hdg
=0.8×800×10
=6400Pa
Therefore, pressure exerted by the alcohol column is 6400 Pa.
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