Question

Calculate the pressure exerted by 1023 gas molecules each of mass 10−22 g in a container of volume one litre. The rms speed is 105cmsec−1

Answer 1

Given

n = 1023

m=10−22g

V = 1 litre = 103cm3

Urms=105cmsec−1

PV = 13mnu2rms

P×103=13×10−22×1023×(105)2

P=3.3×107dynecm−2

Hence answer is (c)