Question

Calculate the pressure exerted by 6 cm of water on it's base in the SI unit. Density of water is 1000 kg/m^3. [g=10 m/s^2].​

Answer 1

Explanation:

p=hdg

=6/100*1000*10

=600Pa

Answer 2

Answer:

588pa or 600pa

Explanation:

IF THE ACCELERATION DUE TO GRAVITY IS GIVEN AS (9.8m/s²)

Then the pressure will be:

GIVEN:

P=?

h=6 cm converted to meter 6÷1000= 0.06m

g=9.8m/s²

pressure(p)= height× density×acceleration due to gravity

pressure= 0.06×1000×9.8

= 588pa.

OR

IN THE CASE OF THE ACCELERATION DUE TO GRAVITY GIVEN AS 10m/s²

THEN:

pressure= 0.06×1000×10

= 600pa.

HOPE THIS HELPS YOU !

PLEASE MARK ME AS THE BRAINLIEST