Question

calculate the pressure exerted by 6 cm of water on its base in si unit density of water is 1000kg/m3 g=10 m/s2​

Answer 1

Answer:

Pressure=h×d×g

= 0.06m×1000×10

600pa

Explanation: As we have to calculate ans in SI unit ,so we first convert 6cm into metres and then calculate our answer .. instead of Pascal we can also use Newton per metre square.

Answer 2

The Pressure exerted by the water is 600 Pa

Explanation:

Given Data

Height of the water = 6 cm

In meter, Height of the water = 0.06 m

Density of the water = 1000 kg /m³

Acceleration due to gravity = 10 m/s²

Find the pressure exerted by the water.

• The force which is physically applied on an object is termed as Pressure.
• Atmospheric, Absolute, Differentiate, Gauge are the types of pressure.
• Pressure is equal to the force applied on a given area.

                        $\text{Pressure} = \frac{\text{Force}}{\text{Area}} \ (\text{N/m}^2)$

              $\text{Pressure} = \text{Height} \times \text{Density} \times \text{Gravity} \ (\text{Pa})$

Pressure = Height × Density × Gravity  (Pa)

Substitute the respective values in above equation

Pressure = 0.06 × 1000 × 10

Pressure = 60 × 10

Pressure = 600 Pa

Therefore the pressure exerted by the water on its base is 600 Pa.

To Learn More

1) A body of mass 2kg and density 8000 kg per metre cube is completely dipped in a liquid of density 800 kg per metre cube. Find the force of buoyancy on it.

https://brainly.in/question/2022643

2) The area of base of a cylindrical vessel is 300 cm^2 square water density equals 1000 kg m^-3 is poured into up to a depth of 6 CM calculate  (a) the pressure and  (b) the trust of water on the base is equals to 10 ns^-2

https://brainly.in/question/1565479