Calculate the pressure exerted by a block of 108 surface area of contact is 2.5 metre square
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Given,
Force exerted by the object, F = 108 N
Surface area of contact, a = 2.5 m²
We have to find,
Pressure exerted by the object, P
We know that,
Pressure is equal to the value of Force divided by area, i.e.,

Assigning the values from the question,


Hence, a block of area 2.5 m/s² and a Force 108 N exerts a pressure of 43.2 N/m².
That's your answer.
Hope it'll help.. :-D
Force exerted by the object, F = 108 N
Surface area of contact, a = 2.5 m²
We have to find,
Pressure exerted by the object, P
We know that,
Pressure is equal to the value of Force divided by area, i.e.,
Assigning the values from the question,
Hence, a block of area 2.5 m/s² and a Force 108 N exerts a pressure of 43.2 N/m².
That's your answer.
Hope it'll help.. :-D
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