Physics, asked by LN123, 10 months ago

Calculate the pressure exerted by a block of iron which applies a force of 10N, when it is kept on its widest base on the soil. The dimensions of the block is 20cm,10cm and 5cm.

Answers

Answered by PritamRoyChowdhury
5

Answer:

5*10^2 N/m^2

Explanation:

PRESSURE APPLIED =FORCE /AREA

FORCE=10N (given)

AREA= 20*10=200cm^2 (given that the block is kept in widest base on the soil)

=2*10^-2 m^2

therefore,

PRESSURE =10/2*10^-2 = 5*10^2 N/m^2

Answered by runumidevi074
1

Answer:

500 pascle

Explanation:

The brick is in its widest base I.e the lower rectangular base with dimensions 20cm and 10cm...

W/k

Pressure = force /area

Given force exerted = 10N

Area of a rectangle= lenght ×breadth

=0.2×0.1=0.02m^2

Therefore pressure=10/0.02

=500 pa

Similar questions